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迭代器3: exercises/iterators/iterators3.rs
题目
rust
// iterators3.rs
//
// This is a bigger exercise than most of the others! You can do it! Here is
// your mission, should you choose to accept it:
// 1. Complete the divide function to get the first four tests to pass.
// 2. Get the remaining tests to pass by completing the result_with_list and
// list_of_results functions.
//
// Execute `rustlings hint iterators3` or use the `hint` watch subcommand for a
// hint.
// I AM NOT DONE
#[derive(Debug, PartialEq, Eq)]
pub enum DivisionError {
NotDivisible(NotDivisibleError),
DivideByZero,
}
#[derive(Debug, PartialEq, Eq)]
pub struct NotDivisibleError {
dividend: i32,
divisor: i32,
}
// Calculate `a` divided by `b` if `a` is evenly divisible by `b`.
// Otherwise, return a suitable error.
pub fn divide(a: i32, b: i32) -> Result<i32, DivisionError> {
todo!();
}
// Complete the function and return a value of the correct type so the test
// passes.
// Desired output: Ok([1, 11, 1426, 3])
fn result_with_list() -> () {
let numbers = vec![27, 297, 38502, 81];
let division_results = numbers.into_iter().map(|n| divide(n, 27));
}
// Complete the function and return a value of the correct type so the test
// passes.
// Desired output: [Ok(1), Ok(11), Ok(1426), Ok(3)]
fn list_of_results() -> () {
let numbers = vec![27, 297, 38502, 81];
let division_results = numbers.into_iter().map(|n| divide(n, 27));
}
#[cfg(test)]
mod tests {
use super::*;
#[test]
fn test_success() {
assert_eq!(divide(81, 9), Ok(9));
}
#[test]
fn test_not_divisible() {
assert_eq!(
divide(81, 6),
Err(DivisionError::NotDivisible(NotDivisibleError {
dividend: 81,
divisor: 6
}))
);
}
#[test]
fn test_divide_by_0() {
assert_eq!(divide(81, 0), Err(DivisionError::DivideByZero));
}
#[test]
fn test_divide_0_by_something() {
assert_eq!(divide(0, 81), Ok(0));
}
#[test]
fn test_result_with_list() {
assert_eq!(format!("{:?}", result_with_list()), "Ok([1, 11, 1426, 3])");
}
#[test]
fn test_list_of_results() {
assert_eq!(
format!("{:?}", list_of_results()),
"[Ok(1), Ok(11), Ok(1426), Ok(3)]"
);
}
}
这次的练习要比其他的练习稍微复杂一点,但是相信您可以的,这是您的使命:
- 完成除法函数,以使前4个单元测试通过
- 通过完成
rust_with_list
和list_of_results
函数来通过剩余的测试。
题目解析
第一个函数的作用是:如果a
能被b
整除,则计算a
除以b
的值。否则,返回一个合适的错误。
rust
pub fn divide(a: i32, b: i32) -> Result<i32, DivisionError> {
if b == 0 {
Err(DivisionError::DivideByZero)
} else if a % b == 0 {
Ok(a / b)
} else {
Err(DivisionError::NotDivisible(NotDivisibleError {
dividend: a,
divisor: b,
}))
}
}
第二个函数的作用为是对一个Vec执行整除操作,最终要将结果也以一个Ok(Vec<i32>)
返回:
rust
fn result_with_list() -> Result<Vec<i32>, DivisionError> {
let numbers = vec![27, 297, 38502, 81];
let division_results = numbers.into_iter().map(|n| divide(n, 27));
division_results.collect()
}
第三个函数的作用与第二个类似,但是是在Vec中存储每一个整除的结果:
rust
fn list_of_results() -> Vec<Result<i32, DivisionError>> {
let numbers = vec![27, 297, 38502, 81];
let division_results = numbers.into_iter().map(|n| divide(n, 27));
division_results.collect()
}