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生命周期1:exercises/lifetimes/lifetimes1.rs
题目
rust
// lifetimes1.rs
//
// The Rust compiler needs to know how to check whether supplied references are
// valid, so that it can let the programmer know if a reference is at risk of
// going out of scope before it is used. Remember, references are borrows and do
// not own their own data. What if their owner goes out of scope?
//
// Execute `rustlings hint lifetimes1` or use the `hint` watch subcommand for a
// hint.
// I AM NOT DONE
fn longest(x: &str, y: &str) -> &str {
if x.len() > y.len() {
x
} else {
y
}
}
fn main() {
let string1 = String::from("abcd");
let string2 = "xyz";
let result = longest(string1.as_str(), string2);
println!("The longest string is '{}'", result);
}
Rust编译器需要知道如何检查提供的引用是否有效,以便它可以让程序在使用引用之前知道引用是否超出了存活周期。请记住,引用是借用的,并不拥有自己的数据所有权。如果超出出借人的存活周期怎么办?
题目解析
函数fn longest(x: &str, y: &str) -> &str
中两个参数和一个返回值都使用了引用的形式,可能返回x,也可能返回y,所以两个参数和返回的引用存活的一样久。
rust
fn longest(x: &str, y: &str) -> &str {
fn longest<'a>(x: &'a str, y: &'a str) -> &'a str {
if x.len() > y.len() {
x
} else {
y
}
}